🚀 Programming Example

Armstrong Number in C#

👁 471 Views

💻 Practical Program

📘 Step Learning

In this section you will learn about Armstrong Number in C# programming language with example and code.

📌 Information & Algorithm

Before going to write the C# program to check whether the number is Armstrong or not, let's understand what is Armstrong number.

Armstrong number is a number that is equal to the sum of cubes of its digits. For example 0, 1, 153, 370, 371 and 407 are the Armstrong numbers.

Let's try to understand why 371 is an Armstrong number.


 371 = (3*3*3)+(7*7*7)+(1*1*1)      
where:      
(3*3*3)=27      
(7*7*7)=343      
(1*1*1)=1      
So:      
27+343+1=371

Know More about Armstrong Number from this link.

💻 Program Code

using System;  
  public class ArmstrongExample  
   {  
     public static void Main(string[] args)  
      {  
       int  n,r,sum=0,temp;      
       Console.Write("Enter the Number= ");      
       n= int.Parse(Console.ReadLine());     
       temp=n;      
       while(n>0)      
       {      
        r=n%10;      
        sum=sum+(r*r*r);      
        n=n/10;      
       }      
       if(temp==sum)      
        Console.Write("Armstrong Number.");      
       else      
        Console.Write("Not Armstrong Number.");      
      }  
  }

🖥 Program Output

Output 1:
Enter the Number= 371
Armstrong Number.

Output 2:
Enter the Number= 342   
Not Armstrong Number.

📘 Explanation

None

🎯 How to learn from this example

First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.

🔥 Practice suggestion

Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.

⚡ Quick Practice Flow

Follow this learning sequence for better understanding.

Read the topic carefully
Understand the algorithm
Study the code line-by-line
Check the output result
Practice by modifying logic