Programming Example

Design a class to overload a function series( ) as follows:

double series(double n) with one double argument and returns the sum of the series.
sum = (1/1) + (1/2) + (1/3) + .......... + (1/n)

double series(double a, double n) with two double arguments and returns the sum of the series.
sum = (1/a²) + (4/a⁵) + (7/a⁸) + (10/a¹¹) + .......... to n terms

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💻 Practical Program

📘 Step by Step Learning

Study this program carefully to understand the logic, output, and explanation in a structured way.

Program Code

public class RAnsariSeries
{
    double series(double n) {
        double sum = 0;
        for (int i = 1; i <= n; i++) {
            double term = 1.0 / i;
            sum += term;
        }
        return sum;
    }

    double series(double a, double n) {
        double sum = 0;
        int x = 1;
        for (int i = 1; i <= n; i++) {
            int e = x + 1;
            double term = x / Math.pow(a, e);
            sum += term;
            x += 3;
        }
        return sum;
    }

    public static void main(String args[]) {
        RAnsariSeries obj = new RAnsariSeries();
        System.out.println("First series sum = " + obj.series(5));
        System.out.println("Second series sum = " + obj.series(3, 8));
    }
}

Output

First series sum = 2.283333333333333
Second series sum = 0.1286982248418103
Press any key to continue . . .

How to learn from this program

First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.

Practice suggestion

After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.

Program Code

Output

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