🚀 Programming Example
Question 6
Learn this program step-by-step with algorithm, source code, output and detailed explanation.
Design a class to overload a function Sum( ) as follows:
(i) int Sum(int A, int B) — with two integer arguments (A and B) calculate and return sum of all the even numbers in the range of A and B.
Sample input: A=4 and B=16
Sample output: sum = 4 + 6 + 8 + 10 + 12 + 14 + 16
(ii) double Sum( double N ) — with one double arguments(N) calculate and return the product of the following series:
sum = 1.0 x 1.2 x 1.4 x . . . . . . . . x N
(iii) int Sum(int N) - with one integer argument (N) calculate and return sum of only odd digits of the number N.
Sample input : N=43961
Sample output : sum = 3 + 9 + 1 = 13
Write the main method to create an object and invoke the above methods.
public class RAnsariSumOverload
{
public int Sum(int A, int B) {
int sum = 0;
for (int i = A; i <= B; i++) {
if (i % 2 == 0)
sum += i;
}
return sum;
}
public double Sum(double N) {
double p = 1.0;
for (double i = 1.0; i <= N; i += 0.2)
p *= i;
return p;
}
public int Sum(int N) {
int sum = 0;
while (N != 0) {
int d = N % 10;
if (d % 2 != 0)
sum += d;
N /= 10;
}
return sum;
}
public static void main(String args[]) {
RAnsariSumOverload obj = new RAnsariSumOverload();
int evenSum = obj.Sum(4, 16);
System.out.println("Even sum from 4 to 16 = " + evenSum);
double seriesProduct = obj.Sum(2.0);
System.out.println("Series Product = " + seriesProduct);
int oddDigitSum = obj.Sum(43961);
System.out.println("Odd Digits Sum = " + oddDigitSum);
}
}
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.