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C program to print right arrow star pattern
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Write a C program to print right arrow star pattern series using for loop. How to print right arrow star pattern structure in C program. Logic to print right arrow star pattern in C programming.

Program Code

/**
 * C program to print right arrow star pattern
 */

#include <stdio.h>

int main()
{
    int i, j, n;

    // Input number of rows from user
    printf("Enter value of n : ");
    scanf("%d", &n);

    // Print the upper part of the arrow
    for(i=1; i<n; i++)
    {
        // Print trailing (2*rownumber-2) spaces
        for(j=1; j<=(2*i-2); j++)
        {
            printf(" ");
        }

        // Print inverted right triangle star pattern
        for(j=i; j<=n; j++)
        {
            printf("*");
        }

        printf("\n");
    }

    // Print lower part of the arrow
    for(i=1; i<=n; i++)
    {
        // Print trailing (2*n - 2*rownumber) spaces
        for(j=1; j<=(2*n - 2*i); j++)
        {
            printf(" ");
        }

        // Print simple right triangle star pattern
        for(j=1; j<=i; j++)
        {
            printf("*");
        }

        printf("\n");
    }

    return 0;
}

Output

Enter value of n : 5
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Explanation

Required knowledge

Basic C programming, For loop, Nested loop

Read more - Program to print left arrow star pattern.

Logic to print right arrow star pattern

This pattern is a combination of two patterns hence, let's first divide it into two parts.

If you have noticed total number of spaces in upper part is 2*rownumber - 2 per row and bottom part contains total 2*n - 2*rownumber spaces per row (where n is the total number of rows). If you ignore leading spaces, then the upper part star pattern is similar to inverted right triangle star pattern and bottom part to simple right triangle star pattern which I already explained how to print.

How to learn from this program

First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.