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Program to print the given number pattern
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/** * C program to print number pattern */ #include int main() { int rows, cols, i, j, k; /* Input rows and columns from user */ printf("Enter number of rows: "); scanf("%d", &rows); printf("Enter number of columns: "); scanf("%d", &cols); k = 1; for(i=1; i<=rows; i++) { for(j=1; j<=cols; j++, k++) { printf("%-3d", k); } printf("\n"); } return 0; }

Program Code

/**
 * C program to print number pattern
 * www.atnyla.com
 */

#include <stdio.h>

int main()
{
    int rows, cols, i, j, k;

    /* Input rows and columns from user */
    printf("Enter number of rows: ");
    scanf("%d", &rows);
    printf("Enter number of columns: ");
    scanf("%d", &cols);

    k = 1;
    for(i=1; i<=rows; i++)
    {
        for(j=1; j<=cols; j++, k++)
        {
            printf("%-3d", k);
        }

        printf("\n");
    }

    return 0;
}

Output

Enter number of rows: 5
Enter number of columns: 5
1  2  3  4  5
6  7  8  9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25

Explanation

Required knowledge

Basic C programming, Loop

Logic to print the given number pattern

Before we get into detail with the current number pattern I recommend you to go through previous number patterns to get basics of printing number pattern.

Now, once you get acquainted with the basics of printing number pattern look to the pattern carefully and you will notice that for each column number gets printed in an incremented fashion. Hence to print this pattern we will use another variable lets say k which will keep track of the number to be printed. Each time the number gets printed we will increment the value of k to get the next number.
Lets, now implement this on code.

How to learn from this program

First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.