1 21 321 4321 54321
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=1; i<=N; i++)
{
// Logic to print numbers
for(j=i; j>=1; j--)
{
printf("%d", j);
}
printf("\n");
}
return 0;
}
Enter N: 5
1
21
321
4321
54321
1 21 321 4321 54321
To get the logic of the given pattern look to the pattern carefully for a minute. If you have noticed the pattern consists of N rows (where N is the total number of rows to be printed). Each row contains exactly icolumns (where i is the current row number). Since the columns are printed in descending order hence, you must run the loop from i to 1 and print the value of j (where j is the current column number).
Step-by-step descriptive logic of the pattern:
Lets now implement this logic.
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.