1 23 345 4567 56789
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, k, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=1; i<=N; i++)
{
k = i;
// Logic to print numbers
for(j=1; j<=i; j++, k++)
{
printf("%d", k);
}
printf("\n");
}
return 0;
}
Enter N: 5
1
23
345
4567
56789
1 23 345 4567 56789
Before I discuss logic to print the given number pattern, I recommend you that have a close look to the pattern carefully for a couple of minutes. The above pattern consists of N rows (where N is the total number of rows to be printed). Each row contains i columns (where i is the current row number). To print the above pattern we will be using an extra variable say k that will keep the value which we need to print.
Step-by-step descriptive logic:
And you are done, lets implement this.
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.