1 23 345 4567 56789
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, k, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=1; i<=N; i++)
{
k = i;
// Logic to print numbers
for(j=1; j<=i; j++, k++)
{
printf("%d", k);
}
printf("\n");
}
return 0;
}
Enter N: 5
1
23
345
4567
56789
1 23 345 4567 56789
Before I discuss logic to print the given number pattern, I recommend you that have a close look to the pattern carefully for a couple of minutes. The above pattern consists of N rows (where N is the total number of rows to be printed). Each row contains i columns (where i is the current row number). To print the above pattern we will be using an extra variable say k that will keep the value which we need to print.
Step-by-step descriptive logic:
And you are done, lets implement this.
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.