#include<stdio.h>
float power(float a , int n);
float Ipower(float a , int n);
main( )
{
float a, p;
int n;
printf("Enter a and n : ");
scanf("%f %d", &a, &n);
p = power(a, n);
printf("%f raised to power %d is %f\n", a, n, p);
p = Ipower(a, n);
printf("%f raised to power %d is %f\n", a, n, p);
}/*End of main()*/
/*Recursive*/
float power(float a , int n)
{
if(n == 0)
return(1);
else
return(a * power(a,n-1));
}/*End of power()*/
/*Iterative*/
float Ipower(float a , int n)
{
int i;
float result=1;
for(i=1; i<=n; i++)
result = result * a;
return result;
}/*End of Ipower()*/
Enter a and n : 1.2
2
1.200000 raised to power 2 is 1.440000
1.200000 raised to power 2 is 1.440000
Press any key to continue . . .
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.