The below code is a C program that demonstrates how to perform arithmetic operations on variables of integer and floating-point data types and print the results to the console using the printf() function.
Here's how it works:
#include line includes the standard input/output library in the program.main() function is the entry point of the program.a, b, and c are declared and initialized with values of 10, 6, and the result of a+b respectively.printf() function prints the values of a, b, and c with the + operator to perform addition and the = operator to assign the result to c.-, * operators to perform subtraction, multiplication operations and assigns the results to c.printf() function performs integer division of a/b and prints the result with two decimal places using the %f format specifier. Note that since a and b are both integers, integer division is performed and the result is truncated to an integer before it is assigned to d.(float)a/b by explicitly casting a to a floating-point value before performing the division operation. The result is then assigned to e.printf() function prints the value of e with two decimal places using the %f format specifier.#include <stdio.h>
int main() {
int a,b,c;
a = 10;
b = 6;
c = a + b;
printf("%d + %d = %d\n",a,b,c);
c = a - b;
printf("%d - %d = %d\n",a,b,c);
c = a * b;
printf("%d * %d = %d\n",a,b,c);
float d = a / b;
printf("%d / %d = %.2f\n",a,b,d);
float e =(float)a / b;
printf("%d / %d = %.2f\n",a,b,e);
return 0;
}
10 + 6 = 16
10 - 6 = 4
10 * 6 = 60
10 / 6 = 1.00
10 / 6 = 1.67
Press any key to continue . . .
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.