🚀 Programming Example
Find the LCM of two Numbers using Command Line Language
Find the LCM of two Numbers using Command Line Language
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char * argv[])
{
int n1,n2,x,y;
if (argc == 1 || argc > 3)
{
printf("Enter Two Number\r\n");
exit(0);
}
x=atoi(argv[1]);
y=atoi(argv[2]);
n1 = x; n2 = y;
while(n1!=n2){
if(n1>n2)
n1=n1-n2;
else
n2=n2-n1;
}
printf("L.C.M of %d & %d = %d \r\n",x,y,x*y/n1);
return 0;
}
10 12
L.C.M of 10 & 12 = 60
#include#include int main(int* argc, char* argv[]) { int a, b, i, gcd, n1, n2; int lcm, lcm1; if(argc==1) { printf(?Not sufficient value provided?); } else { a = atoi( argv[1] ); b = atoi( argv[2] ); n1 = a; n2 = b; for( i = 1 ; i < a && i < b ; i++) { if( a % i == 0 && b % i == 0 ) { gcd=i; } } lcm = (n1*n2)/gcd; lcm1 = (int)lcm; printf("%d",lcm1); } return 0; }
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.