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Qhere are three consecutive odd numbers whose squares have a sum of 2531. Determine the values of these numbers.
ID: #4479
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Given: The sum of the squares of three consecutive odd numbers is 2531 Find: The values of these numbers Let the three consecutive odd numbers be x, x + 2, and x + 4. Then the sum of their squares is given by: x^2 + (x + 2)^2 + (x + 4)^2 = 2531 Expand and rearrange the terms: 3x^2 + 12x - 2511 = 0 Factor the quadratic equation: (x - 27)(x + 31) = 0 Solve for x: x = 27 Therefore, the three numbers are x = 27, x + 2 = 27 + 2 = 29, and x + 4 = 27 + 4 = 31.
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