Write a Java program to find out whether a year (entered in 4-digit number representing it) is a leap year.

Java Programming Language Decision Making in java (Article) Decision Making in java (Program)

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Given Input:

Enter a 4-digit year: 2024

Expected Output:

2024 is a Leap Year.

Program:

import java.util.Scanner;

public class LeapYearCheck {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        System.out.print("Enter a 4-digit year: ");
        int year = sc.nextInt();

        // Check if year is 4-digit
        if (year < 1000 || year > 9999) {
            System.out.println("Invalid input! Please enter a 4-digit year.");
        } 
        else {
            // Leap year condition
            if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
                System.out.println(year + " is a Leap Year.");
            } else {
                System.out.println(year + " is NOT a Leap Year.");
            }
        }

        sc.close();
    }
}

Output:

Explanation:

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