Identifying Whitespace Characters with isWhitespace() Method in Java: A Comprehensive Guide

Description

The method determines whether the specified char value is a white space, which includes space, tab, or new line.

Method Syntax

public static boolean isWhitespace(char ch)

Method Argument

Method Returns

This method returns true, if the passed character is really a white space.

Compatibility

Requires Java 1.1 and up

Example

Below is a simple java example on the usage of isWhitespace(char ch) method of Character class.

public class MethodisWhitespace {

   public static void main(String args[]) {
      System.out.println(Character.isWhitespace('d'));
      System.out.println(Character.isWhitespace(' '));
      System.out.println(Character.isWhitespace('\n'));
      System.out.println(Character.isWhitespace('\t'));
   }
}

output

Below is the sample output when you run the above example.

false
true
true
true
Press any key to continue . . .

Example

Below is a simple java example on the usage of isWhitespace(char ch) method of Character class.

import java.util.Scanner;

/*
 * This example source code demonstrates the use of
 * isWhitespace(char ch) method of Character class.
 */

public class CharacterIsWhiteSpaceChar  {

	public static void main(String[] args) {

		// Ask for user input
		System.out.print("Enter an input:");

		// use scanner to get the user input
		Scanner s = new Scanner(System.in);

		// gets the user input
		char[] value = s.nextLine().toCharArray();

		// close the scanner object
		s.close();

		// check if user input is white space
		for (char ch : value) {
			boolean result = Character.isWhitespace(ch);
			// print the result
			System.out.println("character " + ch
					+ " is a white space? " + result);
		}

	}

}

output

Below is the sample output when you run the above example.

Enter an input:s
character s is a white space? false
Press any key to continue . . .


Enter an input:
character   is a white space? true
Press any key to continue . . .