Python Two Sum
Two Sum
Two Sum
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
Input: nums = [3,2,4], target = 6 Output: [1,2]
Input: nums = [3,3], target = 6 Output: [0,1]
Constraints:
2 <= nums.length <= 104-109 <= nums[i] <= 109-109 <= target <= 109Follow-up: Can you come up with an algorithm that is less than O(n2) time complexity?
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
num_indices = {}
for i, num in enumerate(nums):
complement = target - num
if complement in num_indices:
return [num_indices[complement], i]
num_indices[num] = i
return None # if no solution is found
Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.