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Explanatory Question

Which arithmetic operations can result in the throwing of an ArithmeticException?

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📘 Detailed Answer
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Answer with Explanation

In Java, the ArithmeticException is mainly thrown during arithmetic operations that result in illegal or undefined results, particularly division by zero using integer types.

💡 Detailed Explanation:

The only arithmetic operation that can cause an ArithmeticException in Java is:

Integer division or modulus (%) by zero.

🧮 Examples:

✅ Example 1 — Division by zero


int a = 10;
int b = 0;
int c = a / b; // ❌ Throws ArithmeticException: / by zero

✅ Example 2 — Modulus by zero

 

int x = 25;
int y = 0;
int z = x % y; // ❌ Throws ArithmeticException: / by zero

⚙️ Note:

  • This exception occurs only with integer types (int, long, short, byte).

  • Floating-point division (float, double) does not throw an exception — it results in:

    • Infinity (for positive/negative division by zero), or

    • NaN (Not a Number).

Example:

 

double a = 10.0;
double b = 0.0;
System.out.println(a / b); // ✅ Outputs: Infinity

🧠 Summary:

In Java, integer division (/) or modulus (%) by zero are the operations that can throw an ArithmeticException.