Which arithmetic operations can result in the throwing of an ArithmeticException?

Question

Accepted Answer

In Java, the ArithmeticException is mainly thrown during arithmetic operations that result in illegal or undefined results, particularly division by zero using integer types.

💡 Detailed Explanation:
The only arithmetic operation that can cause an ArithmeticException in Java is:

Integer division or modulus (%) by zero.


🧮 Examples:
✅ Example 1 &mdash; Division by zero


 

 


int a = 10;
int b = 0;
int c = a / b; // ❌ Throws ArithmeticException: / by zero
 


✅ Example 2 &mdash; Modulus by zero


 

 

int x = 25;
int y = 0;
int z = x % y; // ❌ Throws ArithmeticException: / by zero

 



⚙️ Note:


This exception occurs only with integer types (int, long, short, byte).


Floating-point division (float, double) does not throw an exception &mdash; it results in:


Infinity (for positive/negative division by zero), or


NaN (Not a Number).




Example:


 



double a = 10.0;
double b = 0.0;
System.out.println(a / b); // ✅ Outputs: Infinity




🧠 Summary:

In Java, integer division (/) or modulus (%) by zero are the operations that can throw an ArithmeticException.

Which arithmetic operations can result in the throwing of an ArithmeticException?

Answer with Explanation

💡 Detailed Explanation:

🧮 Examples:

✅ Example 1 — Division by zero

✅ Example 2 — Modulus by zero

⚙️ Note:

Example:

🧠 Summary: