Give the output of the following method: <pre class = "prettyprint"><xmp> public static void main(String args[]){ int a = 5; a++; System.out.println(a); a -= (a--) - (--a); System.out.println(a); } </xmp></pre>

Give the output of the following method: <pre class = "pretty

Single Choice Easy

QGive the output of the following method:


public static void main(String args[]){
    int a = 5;
    a++;
    System.out.println(a);

    a -= (a--) - (--a);
    System.out.println(a);

}

ID: #22238 switch case in Java 126 views

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#22238Q ID

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switch case in JavaTopic

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A 6 4 ✔ ✖
B 5 7 ✔ ✖
C 4 6 ✔ ✖
D 6 6 ✔ ✖

Correct Answer

Explanation

Let's analyze the given Java code to determine its output:

Code:


public static void main(String[] args) {
    int a = 5;
    a++;
    System.out.println(a);
    
    a -= (a--) - (--a);
    System.out.println(a);
}

Explanation:

Initial Code Analysis:

- int a = 5; initializes a with the value 5.
- a++; increments a by 1. After this operation, a becomes 6.
- System.out.println(a); prints the value of a, which is 6.
Second Part of the Code:

- a-- is the post-decrement operator. It returns the value of a before decrementing it. So, a-- evaluates to 6, and then a is decremented to 5.
- --a is the pre-decrement operator. It decrements a first, so --a evaluates to 4, and a becomes 4.
- Therefore, the expression a -= (a--) - (--a) translates to a -= 6 - 4:
- 6 - 4 evaluates to 2.
- Thus, a -= 2 is equivalent to a = a - 2. Since a is 4 at this point, this becomes 4 - 2, which results in 2.
- System.out.println(a); prints the value of a, which is 4.

Conclusion:

The output of the program is:

6 (after the a++ operation)
4 (after the a -= (a--) - (--a) operation)

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QGive the output of the following method: public static void main(String args[]){ int a = 5; a++; System.out.println(a); a -= (a--) - (--a); System.out.println(a); }