switch case in Java - Quiz

Let's determine the final values stored in the variables x and y based on the given code:

Code:

double a = 6.35;
double b = 14.74;

double x = Math.abs(Math.ceil(a));
double y = Math.rint(Math.max(a, b));
        

Explanation:

1. Calculating the Value of x:

   Math.ceil(a):
   The Math.ceil(x) method returns the smallest integer greater than or equal to x.
   For a = 6.35, Math.ceil(6.35) returns 7.0.

   Math.abs(Math.ceil(a)):
   The Math.abs(x) method returns the absolute value of x.
   Since Math.ceil(a) is 7.0, and 7.0 is already positive, Math.abs(7.0) remains 7.0.

   So, the value of x is 7.0.

2. Calculating the Value of y:

   Math.max(a, b):
   The Math.max(x, y) method returns the greater of the two values.
   For a = 6.35 and b = 14.74, Math.max(6.35, 14.74) returns 14.74.

   Math.rint(Math.max(a, b)):
   The Math.rint(x) method returns the double value that is closest to x. If two double values are equally close, the even one is returned.
   For Math.max(a, b) which is 14.74, Math.rint(14.74) returns 15.0 because 15.0 is the nearest integer to 14.74.

   So, the value of y is 15.0.

Conclusion:

The final values stored in variables x and y are:

• x: 7.0
• y: 15.0

Let's analyze the given Java code segment to determine its output:

Code:

int i;
for (i = 5; i > 10; i++)
    System.out.println(i);

System.out.println(1 * 4);
        

Explanation:

1. For Loop Analysis:

   for (i = 5; i > 10; i++):
   - **Initialization:** i is initialized to 5.
   - **Condition:** The loop runs while i > 10.
   - **Update:** i is incremented by 1 after each iteration.
   Since i starts at 5 and 5 is not greater than 10, the loop condition is false from the beginning. Therefore, the loop body does not execute even once.

2. Next Line of Code:

   System.out.println(1 * 4);:
   - This statement prints the result of the expression 1 * 4, which is 4.

Conclusion:

The program does not produce an error, run infinitely, or run 5 times. The output of the program is:

• 4

Automatic conversion of primitive data into an object of a wrapper class is called autoboxing.

Explanation:

• Autoboxing is a feature in Java that allows automatic conversion between primitive types (such as int, float, double, etc.) and their corresponding wrapper classes (such as Integer, Float, Double, etc.).
• For example, Java automatically converts an int to an Integer when it is assigned to an Integer object or used in a context where an Integer is expected.

Correct Answer:

a) autoboxing

The parseLong() function is a member of the Long wrapper class.

Explanation:

• parseLong() is a static method provided by the Long wrapper class in Java.
• It is used to convert a String into a long value.

Correct Answer:

a) Long wrapper class

The method used to extract a single character from a String object in Java is charAt().

Explanation:

• charAt(int index) is a method of the String class that returns the character at the specified index in the string. The index is zero-based, meaning the first character is at index 0.

Correct Answer:

c) charAt()

• Assertion (A): The String class in Java is immutable.

  • True. In Java, once a String object is created, it cannot be changed. Any modification to a String object results in the creation of a new String object.

• Reason (R): Immutable objects cannot be modified once they are created, and any operation on a String object results in the creation of a new String object.

  • True. This is a correct explanation of immutability. Since String objects are immutable, any operation that appears to modify a String actually creates a new String object.

Correct Answer:

a) Both Assertion(A) and Reason(R) are true and Reason(R) is correct explanation of Assertion(A).

To stop the execution of a construct, such as a loop or a switch statement, the correct statement is:

b) break

Explanation:

• break: This statement is used to exit from a loop (like for, while, or do-while) or a switch statement. When break is encountered, the execution of the loop or switch construct is immediately terminated.

• System.exit(0): This terminates the entire Java Virtual Machine (JVM), not just a single construct.

• stop: This is not a valid Java statement for stopping execution.

• end: This is not a valid Java statement for stopping execution.

Correct Answer:

b) break

Let's analyze the given Java code to determine its output:

Code:

public static void main(String[] args) {
    int a = 5;
    a++;
    System.out.println(a);
    
    a -= (a--) - (--a);
    System.out.println(a);
}
        

Explanation:

1. Initial Code Analysis:

   - int a = 5; initializes a with the value 5.
   - a++; increments a by 1. After this operation, a becomes 6.
   - System.out.println(a); prints the value of a, which is 6.

2. Second Part of the Code:

   - a-- is the post-decrement operator. It returns the value of a before decrementing it. So, a-- evaluates to 6, and then a is decremented to 5.
   - --a is the pre-decrement operator. It decrements a first, so --a evaluates to 4, and a becomes 4.
   - Therefore, the expression a -= (a--) - (--a) translates to a -= 6 - 4:

   • 6 - 4 evaluates to 2.
   • Thus, a -= 2 is equivalent to a = a - 2. Since a is 4 at this point, this becomes 4 - 2, which results in 2.

   - System.out.println(a); prints the value of a, which is 4.

Conclusion:

The output of the program is:

• 6 (after the a++ operation)
• 4 (after the a -= (a--) - (--a) operation)

Let's analyze the corrected Java code to determine its type:

Corrected Code:

class Out {

    int a = 5; // Adding a variable to compare with x

    int cal() {
        int x = 10;
        if (x > a) {
            return --x; // Decrements x by 1 and returns 9
        } else {
            return ++x; // Increments x by 1 and returns 11
        }
    }

    public static void main(String[] args) {
        Out ob = new Out(); // Create an instance of the class
        int x = ob.cal(); // Call the method cal() and store the result in x
        System.out.println(x); // Print the value of x
    }
}
        

Explanation:

The method cal() performs an operation based on the class-level variable a and modifies the value of x. It returns 9 in this case, because x is greater than a.
- The method is considered an impure method because it depends on and operates based on mutable state.

Answer:

The program demonstrates an example of an Impure Method.

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