- AO(1)
- BO(log n)
- CO(n)
- DO(n^2)
Data Structure - Quiz
- A O(1)
- B O(log N)
- C O(N)
- D O(N^2)
- A O(N)
- B O(log N)
- C O(N^2)
- D O(N log N)
- A O(N)
- B O(log N)
- C O(N^2)
- D O(E + V log V), where E is the number of edges and V is the number of vertices.
- A O(N)
- B O(log N)
- C O(2^N)
- D O(N^2)
- A O(N)
- B O(log N)
- C O(N^2)
- D O(V^3), where V is the number of vertices.
- A O(1)
- B O(log N)
- C O(N)
- D O(N^2)
- A O(N)
- B O(log N)
- C O(N^2)
- D O(N + k), where k is the range of input values.
- A 1 1 1
- Bnull null null
- C0 0 0
- DCompilation error
Results:
🟢 Correct Answers: 🔴 Wrong Answers:
🟢 Correct Answers: 🔴 Wrong Answers:
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Quiz Analytics
Data Structure - Quiz
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Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. O(1)
- B. O(log n)
- C. O(n)
- D. O(n^2)
Remarks:
Explanation:
Answer: O(n)
Explanation: The dynamic programming algorithm for computing the nth Fibonacci number using memoization has a space complexity of O(n) because it involves storing the solutions to n subproblems in memory.
- A. O(1)
- B. O(log N)
- C. O(N)
- D. O(N^2)
Remarks:
Explanation:
Binary search in a balanced BST has a time complexity of O(log N) where N is the number of elements. This is due to the logarithmic reduction in the search space with each comparison.
- A. O(N)
- B. O(log N)
- C. O(N^2)
- D. O(N log N)
Remarks:
Explanation:
Merge sort has a time complexity of O(N log N), making it a stable and efficient sorting algorithm.
- A. O(N)
- B. O(log N)
- C. O(N^2)
- D. O(E + V log V), where E is the number of edges and V is the number of vertices.
Remarks:
Explanation:
Dijkstra's algorithm has a time complexity of O(E + V log V) for finding the shortest path in a graph.
- A. O(N)
- B. O(log N)
- C. O(2^N)
- D. O(N^2)
Remarks:
Explanation:
The recursive generation of the Fibonacci sequence has an exponential time complexity of O(2^N).
- A. O(N)
- B. O(log N)
- C. O(N^2)
- D. O(V^3), where V is the number of vertices.
Remarks:
Explanation:
The Floyd-Warshall algorithm has a cubic time complexity of O(V^3) for finding all-pairs shortest paths in a weighted graph.
- A. O(1)
- B. O(log N)
- C. O(N)
- D. O(N^2)
Remarks:
Explanation:
The pop operation in a queue has a constant-time complexity of O(1), making it efficient for removing elements from the front of the queue.
- A. O(N)
- B. O(log N)
- C. O(N^2)
- D. O(N + k), where k is the range of input values.
Remarks:
Explanation:
Counting sort has a time complexity of O(N + k), where N is the number of elements and k is the range of input values.
- A. List
- B. Map
- C. Set
- D. Struct
Remarks:
Explanation:
Why
The correct answer is:
✅ Map
✅ Explanation:
When you need to cache values for a specific record in Dynamics 365 Finance (X++), the most appropriate collection class is:
✔️
Map
Why Map?
-
Mapis a key-value pair collection. -
You can store a record ID (or any unique identifier) as the key, and the associated data (like a cached value or object) as the value.
-
It allows for efficient retrieval based on the key, making it perfect for caching scenarios.
❌ Why the other options are incorrect:
-
List
❌ Ordered collection without key-based lookup. You'd have to iterate to find a record — not efficient for caching. -
Set
❌ Holds unique values but doesn't store key-value pairs, so you can't map values to a specific record. -
Struct
❌ Used to group related fields together (like a lightweight object), but not suitable for storing multiple records or caching by key.
✅ Final Answer:
✔ Map
- A. 1 1 1
- B. null null null
- C. 0 0 0
- D. Compilation error
Remarks:
Explanation: Answer: c) 0 0 0