- A1
- B10
- C2
- D00
ICSE Computer Application - Class X - 2025 PYQ - Quiz
- Afor(int i=1; i<=10; i++)
- Bfor(int i=2; i!=0; i-=3)
- Cfor(int i=5; j<=5; j++)
- Dfor(int i=1; i>=1; i--)
- A -5
- B-4
- C-7
- Derror
- AGame is an object of cricket class
- BNew keyword creates object Game
- CGame is a class and cricket is an object
- DGame and cricket are objects
- Apublic
- Blocal
- Cprotected
- Dprivate
- ABoth (A) and (R) are true and (R) is a correct explanation of (A).
- BBoth (A) and (R) are true and (R) is not a correct explanation of (A).
- C(A) is true and (R) is false.
- D(A) is false and (R) is true.
- ABoth (A) and (R) are true and (R) is a correct explanation of (A).
- B Both (A) and (R) are true and (R) is not a correct explanation of (A).
- C(A) is true and (R) is false.
- D(A) is false and (R) is true.
- ADouble.Parsedouble("25")
- BDouble.parse("25")
- CDouble.parseDouble("25")
- D Double.parseDouble(25)
Results:
🟢 Correct Answers: 🔴 Wrong Answers:
🟢 Correct Answers: 🔴 Wrong Answers:
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Quiz Information
Quiz Information
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Quiz Analytics
ICSE Computer Application - Class X - 2025 PYQ - Quiz
Guest User
Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. 1
- B. 10
- C. 2
- D. 00
Remarks:
Explanation:
The output of \( 42 \div 6 \mod 2 \) is:
- (a) \( 1 \)
- (b) \( 10 \)
- (c) \( 2 \)
- (d) \( 0 \)
Let's break down the expression step by step:
\[ 42 \div 6 \mod 2 \]
Step 1: Division
\[ 42 \div 6 = 7 \]
Step 2: Modulus Operation
\[ 7 \mod 2 \]
The modulus operator (\%) gives the remainder when dividing 7 by 2.
\[ 7 \div 2 = 3 \text{ remainder } 1 \]
So,
\[ 7 \mod 2 = 1 \]
Final Answer:
(a) 1 ✅
- A. for(int i=1; i<=10; i++)
- B. for(int i=2; i!=0; i-=3)
- C. for(int i=5; j<=5; j++)
- D. for(int i=1; i>=1; i--)
Remarks:
Explanation:
Correct Infinite Loop
Let's check the correct infinite loop:
for(int i=2; i!=0; i-=3)
Loop Breakdown:
-
Step 1:
i = 2(Conditioni != 0is true → executes) -
Step 2:
i -= 3(Nowi = -1) -
Step 3:
i != 0? Still true → executes again -
Step 4:
i -= 3(Nowi = -4) -
Step 5:
i != 0? Still true → executes again... -
This never stops because
iwill always be!= 0.
✅ Correct Answer: (b) for(int i=2; i!=0; i-=3) (Infinite Loop)
- A. -5
- B. -4
- C. -7
- D. error
Remarks:
Explanation:
(b) -4
Explanation: Math.min(-5, -4) → -5, then Math.max(-7, -5) → -5 (Correct answer: -5).
- A. Game is an object of cricket class
- B. New keyword creates object Game
- C. Game is a class and cricket is an object
- D. Game and cricket are objects
Remarks:
Explanation:
(c) Game is a class and cricket is an object
Explanation: Game is the class, new Game(); creates an object named cricket.
- A. public
- B. local
- C. protected
- D. private
Remarks:
Explanation:
(a) public
Explanation: A post office is accessible to everyone, similar to public access specifier.
- A. Both (A) and (R) are true and (R) is a correct explanation of (A).
- B. Both (A) and (R) are true and (R) is not a correct explanation of (A).
- C. (A) is true and (R) is false.
- D. (A) is false and (R) is true.
Remarks:
Explanation:
(a) Both (A) and (R) are true, and (R) is a correct explanation of (A)
Explanation: The break statement prevents fall-through in a switch case by stopping execution after a case is matched.
- A. if
- B. switch
- C. for
- D. if else if
Remarks:
Explanation:
c) for
Explanation: The for loop is used for a fixed number of repetitions (10 times).
- A. Both (A) and (R) are true and (R) is a correct explanation of (A).
- B. Both (A) and (R) are true and (R) is not a correct explanation of (A).
- C. (A) is true and (R) is false.
- D. (A) is false and (R) is true.
Remarks:
Explanation:
(a) Both (A) and (R) are true, and (R) is a correct explanation of (A)
Explanation: A clock's hour and minute hands resemble nested loops, where the minute hand completes a full cycle for each hour hand movement.
- A. Double.Parsedouble("25")
- B. Double.parse("25")
- C. Double.parseDouble("25")
- D. Double.parseDouble(25)
Remarks:
Explanation:
(c) Double.parseDouble("25")
Explanation: The parseDouble() method converts a String to a double. The correct syntax is Double.parseDouble("25").
- A. 3
- B. -6
- C. 6
Remarks:
Explanation:
The compareTo() method compares two strings lexicographically.
-
"ANGER".compareTo("ANGEL")compares characters at each position. -
'R' - 'L' = 82 - 76 = 6, so the result is6. -
Since "ANGER" comes after "ANGEL" lexicographically, the result should be positive.
-
Correct answer: (c)
6(Correction from previous choice!)