Electrostatics - Quiz

The term permittivity, often referred to as the dielectric constant, is a fundamental property of a material that determines its ability to store electrical energy in the presence of an electric field. It measures the degree to which the material can be polarized when subjected to an electric field. In other words, permittivity quantifies the electric field response of a material and its capacity to store electrostatic energy.

The susceptibility of free space or air is zero (0). In free space, the relative permittivity (εr) is equal to 1, and the susceptibility (χe) is given by χe = εr - 1 = 1 - 1 = 0. This means that free space does not exhibit any polarization or ability to become polarized under the influence of an electric field.

The electric potential at a point due to a point charge q is given by V = q/r, where r is the distance between the charge and the point. Therefore, the electric potential due to a point charge q at a distance r in the air is qr.

The electric potential due to a point charge q at a distance r is given by V = (1/4πε) * (q/r), where ε is the permittivity of the medium. Substituting the values, we get V = (9 * 10^9 * 10) / (0.08) = 1.125 * 10^12V.

The electric field intensity E at a distance r from a point charge q is given by E = k*q/r^2, where k is the electrostatic constant. The electric potential V at that distance is given by V = k*q/r. Given that E = 32 N/C and V = 16 J/C, we can equate the two expressions and solve for r. Therefore, 32 N/C = (16 J/C) / r. Rearranging the equation, we have r = (16 J/C) / 32 N/C = 0.5 m.

The electric potential energy of a system depends on the positions and magnitudes of the charges involved. In this case, since all three charges are positive, there are no negative

Yes, electric field and electric field intensity are related to electric potential. The electric field (E) is the negative gradient of the electric potential (V) in the x direction. It represents the rate of change of potential with respect to distance. Therefore, there exists a relationship between electric field and electric potential.

In a charged conductor, the charges distribute themselves uniformly on its surface. This distribution of charges creates an electric field inside the conductor. However, within a conductor, the electric field is zero, and therefore, the potential is constant throughout its surface, making it an equipotential surface. The electric field lines are perpendicular to the surface of the conductor.

In a charged conductor, the charges distribute themselves uniformly on its surface. This distribution of charges creates an electric field inside the conductor. However, within a conductor, the electric field is zero, and therefore, the potential is constant throughout its surface, making it an equipotential surface. The electric field lines are perpendicular to the surface of the conductor.

Points B and C are located on the circle, which represents an equipotential surface. When moving a charge along an equipotential surface, the work done is zero, as there is no change in potential energy. Therefore, the work done in both cases, from A to B and from A to C, is the same and equal to zero.