- A9
- B11
- C \begin{equation} 11 \frac{1}{9} \end{equation}
- D\begin{equation} 11 \frac{2}{9} \end{equation}
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Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. 9
- B. 11
- C. \begin{equation} 11 \frac{1}{9} \end{equation}
- D. \begin{equation} 11 \frac{2}{9} \end{equation}
Remarks:
Explanation: \begin{array}{l}
=\frac{2+3+5+7+11+13+17+19+23}{9} \\
=\frac{100}{9} \\
=11 \frac{1}{9}
\end{array}
- A. 55
- B. 58
- C. 62
- D. 65
Remarks:
Explanation:
The sum of the ages of the two teachers is 62 years.
To find this, we can use the following steps:
The total age of the 30 boys is 450 years.
The total age of the 30 boys and the two teachers is 512 years.
Therefore, the sum of the ages of the two teachers is 512 - 450 = 62 years.
- A. 32
- B. 34
- C. 40
- D. 42
Remarks:
Explanation:
The total age of A and B four years ago: 40 years
The present total age of A and B: 48 years
The present total age of A, B, and C: 75 years
The present age of C: 75 - 48 = 27 years
The age of C after 7 years: 27 + 7 = 34 years.
- A. 30
- B. 31
- C. 33
- D. 35
Remarks:
Explanation:
The weight of Q is 31 kg.
To find this, we can use the following steps:
Let P, Q, and R represent their respective weights.
The sum of the weights of P, Q, and R is 135.
The sum of the weights of P and Q is 80.
The sum of the weights of Q and R is 86.
Adding these two equations gives us P + 2Q + R = 166.
Subtracting the equation for P, Q, and R from this equation gives us Q = 31.
- A. 20.4
- B. 18.34
- C. 17.23
- D. 15.87
Remarks:
Explanation:
The combined average of the two groups is 20.44.
To find this, we can use the following steps:
The number of quantities in group A is 10, and the number of quantities in group B is 8.
The individual average of group A is 24, and the individual average of group B is 16.
The combined total of the two groups is 10 * 24 + 8 * 16 = 240 + 128 = 368.
The total number of quantities in the two groups is 10 + 8 = 18.
Therefore, the combined average of the two groups is 368 / 18 = 20.44.
- A. 24
- B. 26
- C. 30
- D. 32
Remarks:
Explanation:
The sixth number is 30 if the average of 11 numbers is 30,
the average of the first six numbers is 17.5,
and the average of the last six numbers is 42.5.
To find this, we can use the following steps:
Calculate the total of the 11 numbers by multiplying the average value of 30 by 11, which gives us 330.
Calculate the total of the first six numbers by multiplying the average value of 17.5 by 6, which gives us 105.
Calculate the total of the last six numbers by multiplying the average value of 42.5 by 6, which gives us 255.
Find the sixth number by adding the value of the first six and last six numbers and subtracting it from the total value of the 11 numbers,
which gives us (105 + 255) - 330 = 30.
- A. 12
- B. 13
- C. 11
- D. 14
Remarks:
Explanation:
The middle number is 11 if the average of 15 numbers is 15,
the average of the first five numbers is 14, and the average of the other 9 numbers is 16.
To find this, we can use the following steps:
Calculate the total of the 15 numbers by multiplying the average value of 15 by 15, which gives us 225.
Calculate the total of the first five numbers by multiplying the average value of 14 by 5, which gives us 70.
Calculate the total of the other 9 numbers by multiplying the average value of 16 by 9, which gives us 144.
Find the middle number by subtracting the total of the first five and other nine numbers from the total value of the 15 numbers,
which gives us (225) - [(70) + (144)] = 11.
- A. 32
- B. 35
- C. 40
- D. 47
Remarks:
Explanation:
In this question, we are given that John's marks were wrongly entered as 83 instead of 63 and that the average marks for the whole class increased by half as a result.
We are asked to find the number of students in the class.
To solve this problem,
we can first assume the number of students in the class to be x.
We know that the total increase in marks for x students is x/2,
since the average increase is 1/2.
We can then use this information to find the value of x by setting up an equation using the given information.
Specifically, we can set up the equation x/2 = 83 - 63,
which gives us x = 40 students.
This means that there are 40 students in the class.
- A. 26
- B. 27
- C. 25
- D. 24
Remarks:
Explanation:
Output:
Let the ages of the man and his son be 11x and 5x years respectively.
Then the average age =(11x+5x/2)years=8x years
8x=40. X=5
Hence the son's age=5x=25 years
- A. 19.5
- B. 19
- C. 18.5
- D. 18
Remarks:
Explanation:
Solution
Marks in the seventh paper=(42×7×+35×7-40×13)
(294+245-520)=539-520=19