Programming Example
Arithmetic Operators in C, all in one
Study this program carefully to understand the logic, output, and explanation in a structured way.
#include"stdio.h"
void main()
{
int a = 20;
int b = 10;
int c ;
c = a + b;
printf("addition: Value of c is %d\n", c );
c = a - b;
printf("subtraction: Value of c is %d\n", c );
c = a * b;
printf("Multiplication: Value of c is %d\n", c );
c = a / b;
printf("Division: Value of c is %d\n", c );
c = a % b;
printf("Modulo: Value of c is %d\n", c );
c = a++;
printf("Post increment: Value of c is %d\n", c );
c = a--;
printf("post decrement: Value of c is %d\n", c );
c = ++a;
printf("Pre increment: Value of c is %d\n", c );
c = --a;
printf("pre decrement: Value of c is %d\n", c );
}addition: Value of c is 30
subtraction: Value of c is 10
Multiplication: Value of c is 200
Division: Value of c is 2
Modulo: Value of c is 0
Post increment: Value of c is 20
post decrement: Value of c is 21
Pre increment: Value of c is 21
pre decrement: Value of c is 20
Press any key to continue . . .
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.