Programming Example
Logical Operators in C, all in one example 2
Study this program carefully to understand the logic, output, and explanation in a structured way.
// C Program to demonstrate the working of logical operators
#include"stdio.h"
int main()
{
int a = 5, b = 5, c = 10, result;
result = (a = b) && (c > b);
printf("(a = b) && (c > b) equals to %d \n", result);
result = (a = b) && (c < b);
printf("(a = b) && (c < b) equals to %d \n", result);
result = (a = b) || (c < b);
printf("(a = b) || (c < b) equals to %d \n", result);
result = (a != b) || (c < b);
printf("(a != b) || (c < b) equals to %d \n", result);
result = !(a != b);
printf("!(a == b) equals to %d \n", result);
result = !(a == b);
printf("!(a == b) equals to %d \n", result);
return 0;
}(a = b) && (c > b) equals to 1
(a = b) && (c < b) equals to 0
(a = b) || (c < b) equals to 1
(a != b) || (c < b) equals to 0
!(a == b) equals to 1
!(a == b) equals to 0
Press any key to continue . . .
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.