Programming Example
Program to find the average of n (n < 10) numbers using arrays
Program to find the average of n (n < 10) numbers using arrays
/*
Program to find the average of n (n < 10) numbers using arrays
Author: atnyla Developer
*/
#include <stdio.h>
int main()
{
int marks[10], i, n, sum = 0, average;
printf("Enter n: ");
scanf("%d", &n);
for(i=0; i<n; ++i)
{
printf("Enter number%d: ",i+1);
scanf("%d", &marks[i]);
sum += marks[i];
}
average = sum/n;
printf("Average = %d \n", average);
return 0;
}Enter n: 5
Enter number1: 4
Enter number2: 6
Enter number3: 2
Enter number4: 3
Enter number5: 5
Average = 4
Press any key to continue . . .
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.