/* Source code to demonstrate, handling of pointers in C program */
#include <stdio.h>
int main(){
int* pc;
int c;
c=22;
printf("Address of c:%u\n",&c);
printf("Value of c:%d\n\n",c);
pc=&c;
printf("Address of pointer pc:%u\n",pc);
printf("Content of pointer pc:%d\n\n",*pc);
c=11;
printf("Address of pointer pc:%u\n",pc);
printf("Content of pointer pc:%d\n\n",*pc);
*pc=2;
printf("Address of c:%u\n",&c);
printf("Value of c:%d\n\n",c);
return 0;
}
Address of c: 2686784
Value of c: 22
Address of pointer pc: 2686784
Content of pointer pc: 22
Address of pointer pc: 2686784
Content of pointer pc: 11
Address of c: 2686784
Value of c: 2
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.