Programming Example
Accept a character from the user and find it is a vowel or not without using any loop
Accept a character from the user and find it is a vowel or not without using any loop
// Accept a character from the user and find it is a vowel or not without using any loop
#include <stdio.h>
int main()
{
char c;
int isLVowel, isUVowel;
printf("Enter an alphabet: ");
scanf("%c",&c);
isLVowel = (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
isUVowel = (c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
if (isLVowel || isUVowel)
printf("%c is a vowel.", c);
else
printf("%c is a consonant.", c);
return 0;
}Enter an alphabet: e
e is a vowel.
Press any key to continue . . .
First read the algorithm, then study the program code line by line. After that, compare the code with the output and finally go through the explanation. This approach helps learners understand both the logic and the implementation properly.
After understanding this example, try to rewrite the same program without looking at the code. Then change some values or logic and run it again. This helps improve confidence and keeps learners engaged on the page for longer.