✏️ Explanatory Question

What will be the result stored in x after evaluating the following expression? 

int x = 4;
x += (x++) + (++x) + x;

👁 103 Views
📘 Detailed Answer
🟢 Easy
← Previous State the values of n and ch. char c = 'A'; int n = c + 1; char ch = (char)n;
💡

Answer with Explanation


    x += (x++) + (++x) + x
⇒ x = x + ((x++) + (++x) + x)
⇒ x = 4 + (4 + 6 + 6)
⇒ x = 4 + 16
⇒ x = 20


class Student {

    // Main method to create an object of the class and call the member methods
    public static void main(String[] args) {
        int x = 4;
        x += (x++) + (++x) + x;
        System.out.println("The value of x is: " + x); // Corrected to print the value of x
    }
}
← Previous State the values of n and ch. char c = 'A'; int n = c + 1; char ch = (char)n;