State the output when the following program segment is executed:

String a ="Smartphone", b="Graphic Art";
String h=a.substring(2, 5);
String k=b.substring(8).toUpperCase();
System.out.println(h);
System.out.println(k.equalsIgnoreCase(h));

Question

State the output when the following program segment is executed:

String a ="Smartphone", b="Graphic Art";
String h=a.substring(2, 5);
String k=b.substring(8).toUpperCase();
System.out.println(h);
System.out.println(k.equalsIgnoreCase(h));

Accepted Answer

The output of the above code is:


art
true
Explanation
a.substring(2, 5) extracts the characters of string a starting from index 2 till index 4. So h contains the string "art". b.substring(8) extracts characters of b from index 8 till the end so it returns "Art". toUpperCase() converts it into uppercase. Thus string "ART" gets assigned to k. Values of h and k are "art" and "ART", respectively. As both h and k differ in case only hence equalsIgnoreCase returns true.

State the output when the following program segment is executed: String a ="Smartphone", b="Graphic Art"; String h=a.substring(2, 5); String k=b.substring(8).toUpperCase(); System.out.println(h); System.out.println(k.equalsIgnoreCase(h));

Answer with Explanation

Explanation

State the output when the following program segment is executed: