Home / Questions / Give the output of the following code: String A ="26", B="100"; String D=A+B+"200"; int x= Integer.parseInt(A); int y = Integer.parseInt(B); int d = x+y; System.out.println("Result 1 = " + D); System.out.println("Result 2 = " + d);
Explanatory Question

Give the output of the following code: 

String A ="26", B="100";
String D=A+B+"200";
int x= Integer.parseInt(A);
int y = Integer.parseInt(B);
int d = x+y;
System.out.println("Result 1 = " + D);
System.out.println("Result 2 = " + d);

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Answer with Explanation

Output of the above code is:

Result 1 = 26100200
Result 2 = 126
Explanation
  1. As A and B are strings so String D=A+B+"200"; joins A, B and "200" storing the string "26100200" in D.
  2. Integer.parseInt() converts strings A and B into their respective numeric values. Thus, x becomes 26 and y becomes 100.
  3. As Java is case-sensitive so D and d are treated as two different variables.
  4. Sum of x and y is assigned to d. Thus, d gets a value of 126.