Math.sqrt(3 * x + x * x) / (a + b)
Practice with a program
Here's a simple Java program that calculates the given mathematical expression:
public class MathExpression {
public static void main(String[] args) {
// Define values for x, a, and b
double x = 5; // Example value for x
double a = 2; // Example value for a
double b = 3; // Example value for b
// Calculate the expression: Math.sqrt(3 * x + x * x) / (a + b)
double result = Math.sqrt(3 * x + x * x) / (a + b);
// Display the result
System.out.println("Result: " + result);
}
}
Explanation:
3 * x + x * x computes the numerator inside the square root.
Math.sqrt(...) takes the square root of that numerator.
- The denominator is
(a + b).
- The final result is obtained by dividing the square root value by
(a + b).
You can modify the values of x, a, and b to test different cases. đ