Write the value of n after execution:

char ch ='d';
int n = ch + 5;

Question

Write the value of n after execution:

char ch ='d';
int n = ch + 5;

Accepted Answer

Answer
The value of n is 105.

Explanation


char ch = 'd'; assigns the character 'd' to the variable ch. In ASCII, the character 'd' has a decimal value of 100.
int n = ch + 5; adds 5 to the ASCII value of 'd', which is 100. So, 100 + 5 equals 105.

Therefore, the value of n will be 105.

Write the value of n after execution: char ch ='d'; int n = ch + 5;

Answer with Explanation

Explanation

Write the value of n after execution:

char ch ='d'; int n = ch + 5;