Arithmetic Aptitudes → Problems on H.C.F and L.C.M → MCQ Details
MCQ Practice Single Best Answer Topic: Problems on H.C.F and L.C.M

Q Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Question ID
#19257
Subchapter
Problems on H.C.F and L.C.M
Action
Choose one option below

Choose Your Answer

Click an option to check whether your answer is correct.

  • A 4 ✔ ✖
  • B 5 ✔ ✖
  • C 6 ✔ ✖
  • D 7 ✔ ✖
Correct Answer: A

Explanation

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Related Topics

Explore more questions from similar topics.

Alligation or Mixture Area Average Bankers Discount Bar Charts Boats and Streams Calendar Chain Rule Clock Compound Interest Decimal Fraction Height and Distance Line Charts Logarithm Numbers Odd Man Out and Series Partnership Percentage Permutation and Combination Pipes and Cistern Probability Problems on Ages Problems on H.C.F and L.C.M Problems on Numbers Problems on Trains Profit and Loss Races and Games Ratio and Proportion Simple Interest Simplification Square Root and Cube Root Stocks and Shares Surds and Indices Time and Distance Time and Work True Discount Volume and Surface Area

Share This Question

Share this MCQ with your friends or study group.