What will be the output of the program? public class CommandArgsTwo

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QWhat will be the output of the program?

public class CommandArgsTwo 
{
    public static void main(String [] argh) 
    {
        int x;
        x = argh.length;
        for (int y = 1; y <= x; y++) 
        {
            System.out.print(" " + argh[y]);
        }
    }
}

and the command-line invocation is

> java CommandArgsTwo 1 2 3

ID: #1999 Java Language Fundamental 1,724 views

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#1999Q ID

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Java Language FundamentalTopic

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A 0 1 2 ✔ ✖
B 1 2 3 ✔ ✖
C 0 0 0 ✔ ✖
D An exception is thrown at runtime ✔ ✖

Correct Answer

Explanation

An exception is thrown because at some point in (System.out.print(" " + argh[y]);), the value of x will be equal to y, resulting in an attempt to access an index out of bounds for the array. Remember that you can access only as far as length - 1, so loop logical tests should use x < someArray.length as opposed to x < = someArray.length.

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QWhat will be the output of the program?
public class CommandArgsTwo { public static void main(String [] argh) { int x; x = argh.length; for (int y = 1; y <= x; y++) { System.out.print(" " + argh[y]); } } }

and the command-line invocation is

> java CommandArgsTwo 1 2 3

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Explanation

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Related MCQ Questions

QWhat will be the output of the program? public class CommandArgsTwo { public static void main(String [] argh) { int x; x = argh.length; for (int y = 1; y <= x; y++) { System.out.print(" " + argh[y]); } } } and the command-line invocation is > java CommandArgsTwo 1 2 3

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Explanation

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Related MCQ Questions

QWhat will be the output of the program?
public class CommandArgsTwo { public static void main(String [] argh) { int x; x = argh.length; for (int y = 1; y <= x; y++) { System.out.print(" " + argh[y]); } } }

and the command-line invocation is

> java CommandArgsTwo 1 2 3