Q: What are the final values stored in variable x and y below?

double a = 6.35;
double b = 14.74;

double x = Math.abs(Math.ceil(a));
double y = Math.rint(Math.max(a, b));

Let's determine the final values stored in the variables x and y based on the given code:

Code:

double a = 6.35;
double b = 14.74;

double x = Math.abs(Math.ceil(a));
double y = Math.rint(Math.max(a, b));
        

Explanation:

1. Calculating the Value of x:

   Math.ceil(a):
   The Math.ceil(x) method returns the smallest integer greater than or equal to x.
   For a = 6.35, Math.ceil(6.35) returns 7.0.

   Math.abs(Math.ceil(a)):
   The Math.abs(x) method returns the absolute value of x.
   Since Math.ceil(a) is 7.0, and 7.0 is already positive, Math.abs(7.0) remains 7.0.

   So, the value of x is 7.0.

2. Calculating the Value of y:

   Math.max(a, b):
   The Math.max(x, y) method returns the greater of the two values.
   For a = 6.35 and b = 14.74, Math.max(6.35, 14.74) returns 14.74.

   Math.rint(Math.max(a, b)):
   The Math.rint(x) method returns the double value that is closest to x. If two double values are equally close, the even one is returned.
   For Math.max(a, b) which is 14.74, Math.rint(14.74) returns 15.0 because 15.0 is the nearest integer to 14.74.

   So, the value of y is 15.0.

Conclusion:

The final values stored in variables x and y are:

• x: 7.0
• y: 15.0