QWrite the output of the following program code:
char ch;
int x = 97;
do {
ch = (char) x;
System.out.print(ch + " ");
if (x % 10 == 0)
break;
++x;
} while (x <= 100);
Question Info
Choose the Best Option
Click any option to instantly check if you're correct.
Explanation
Let's analyze the given Java code step by step to determine its output:
Code:
char ch;
int x = 97;
do {
ch = (char) x;
System.out.print(ch + " ");
if (x % 10 == 0)
break;
++x;
} while (x <= 100);
Explanation:
-
Initialization:
-
xstarts at97.
- In ASCII,97corresponds to the character 'a'. -
Loop Execution:
First Iteration:
-ch = (char) xconvertsxto the character 'a'.
-System.out.print(ch + " ");prints 'a'.
-x % 10for97is7(not zero), so thebreakstatement is not executed.
-++xincrementsxto98.Second Iteration:
-ch = (char) xconvertsxto the character 'b'.
-System.out.print(ch + " ");prints 'b'.
-x % 10for98is8(not zero), so thebreakstatement is not executed.
-++xincrementsxto99.Third Iteration:
-ch = (char) xconvertsxto the character 'c'.
-System.out.print(ch + " ");prints 'c'.
-x % 10for99is9(not zero), so thebreakstatement is not executed.
-++xincrementsxto100.Fourth Iteration:
-ch = (char) xconvertsxto the character 'd'.
-System.out.print(ch + " ");prints 'd'.
-x % 10for100is0, so thebreakstatement is executed, terminating the loop.
Conclusion:
The final output of the code is:
- a
- b
- c
- d
Share This Question
Challenge a friend or share with your study group.