Programming Language › Operators and Enums in C Language › Question #4164
Single Choice Not Set

QWhat will the the output of the following program? 

#include "stdio.h"

int main() 

{ 

  int x, y = 5, z = 5; 

  x = y == z; 

  printf("%d", x); 

  

  getchar(); 

  return 0; 

}

ID: #4164 Operators and Enums in C Language 399 views
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#4164Q ID
Not SetDifficulty
Operators and Enums in C LanguageTopic
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  • A 00 ✔ ✖
  • B 1 ✔ ✖
  • C 5 ✔ ✖
  • D Compilation error ✔ ✖
Correct Answer

Explanation

The crux of the question lies in the statement x = y==z. The operator == is executed before = because precedence of comparison operators (<=, >= and ==) is higher than assignment operator =. The result of a comparison operator is either 0 or 1 based on the comparison result. Since y is equal to z, value of the expression y == z becomes 1 and the value is assigned to x via the assignment operator.
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