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QWhat is the largest of the four consecutive integers whose sum is 1290?
ID: #4444
Numbers
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The sum of these four integers is 1290, so we can write the equation:
x + (x+1) + (x+2) + (x+3) = 1290
Simplifying this equation, we get:
4x + 6 = 1290
Subtracting 6 from both sides, we get:
4x = 1284
Dividing both sides by 4, we get:
x = 321
So, the four consecutive integers are 321, 322, 323, and 324.
The greatest of these integers is 324.
Therefore, the answer to the question is 324.
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