Given: The ratio between a two-digit number and the sum of the digits of that number is 4:1 The digit in the unit's place is 3 more than the digit in the ten's place Let the digit in the ten's place be x. Then the digit in the unit's place is x + 3 and the sum of the digits is 2x + 3. The two-digit number can be expressed as: 10x + (x + 3) = 11x + 3 The ratio of the number to the sum of its digits is given by: (11x + 3) / (2x + 3) = 4/1 Solve for x: 3x = 9 x = 3 Therefore, the two-digit number is 11x + 3 = 11(3) + 3 = 36.