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QWhat is the largest of the four consecutive even numbers whose average is 27?
ID: #4572
Analogy
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To find the largest of the four consecutive even numbers whose average is 27, we can first assign variables to represent each of the numbers.
Let the numbers be represented by x, x+2, x+4, and x+6.
Then, we can set up the equation
(x+(x+2)+(x+4)+(x+6))/4 = 27
to represent the condition that the average of these four numbers is 27.
Solving this equation yields x = 24, so the largest of the four numbers is x+6 = 24+6 = 30
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