Q: A container contains 50 liters of milk. From this container, 5 liters of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Answer: C

Explanation:

Suppose a container contains X units of a liquid from which Y units are taken out and replaced by water.

After N operations, quantity of pure liquid = X ( 1 - Y / X ) ^ N units

Now, milk exist in the container is = 50 ( 1 - 5 / 50 ) ^ 3

= 50 ( 1 - 1 / 10 ) ^ 3

= 50 * 9/10 * 9/10 * 9/10

= ( 5 * 9 * 9 * 9 ) / 100

= 36.45 liters

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