Q: A container contains 50 liters of milk. From this container, 5 liters of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
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A
22.34 liters
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B
34.65 liters
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C
36.45 liters
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D
12.67 liters
C
Answer:
C
Explanation:
Suppose a container contains X units of a liquid from which Y units are taken out and replaced by water.
After N operations, quantity of pure liquid = X ( 1 - Y / X ) ^ N units
Now, milk exist in the container is
= 50 ( 1 - 5 / 50 ) ^ 3
= 50 ( 1 - 1 / 10 ) ^ 3
= 50 * 9/10 * 9/10 * 9/10
= ( 5 * 9 * 9 * 9 ) / 100
= 36.45 liters
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