- A2%
- B2.02%
- C4%
- D4.04%
Area - Quiz
- A20 square meters
- B35 square meters
- C25 square meters
- D15 square meters
- A130 m2
- B128 m2
- C126 m2
- D124 m2
- A80 cms
- B90 cms
- C50 cms
- DData inadequate
- A420 cm2
- B380 cm2
- C480 cm2
- D410 cm2
- A3 : 17
- B9 : 49
- C24 : 35
- D8 : 23
- A34.56 %
- B32.43 %
- C29.45 %
- D45.24 %
Results:
🟢 Correct Answers: 🔴 Wrong Answers:
🟢 Correct Answers: 🔴 Wrong Answers:
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Quiz Information
Quiz Information
Quiz Platform FAQ
General Information
- Number of Questions: Each quiz consists of 10 questions.
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Quiz Analytics
Area - Quiz
Guest User
Time Taken: Questions: Answered: Not Answered:
Correct Answer:
Wrong Answer:
Percentage: %
- A. 2%
- B. 2.02%
- C. 4%
- D. 4.04%
Remarks:
Explanation:
The percentage error in the calculated area of the square is 4.04%.
This is calculated by taking the difference between the actual area and the measured area, and then expressing it as a percentage of the actual area.
In this case, the actual area is 100cm x 100cm = 10000 cm2 and the measured area is 102cm x 102cm = 10404 cm2
The difference (10404 - 10000) = 404 cm2 which is 4.04% of the actual area.
- A. 20 square meters
- B. 35 square meters
- C. 25 square meters
- D. 15 square meters
Remarks:
Explanation:
Triangle area = 12 * base * height
As a result, the area is 12 * 5 * 10 = 25 square metres.
- A. 130 m<sup>2 </sup>
- B. 128 m<sup>2 </sup>
- C. 126 m<sup>2 </sup>
- D. 124 m<sup>2 </sup>
Remarks:
Explanation:
Area of a square:
side2 = Area Aptitude × (diagonal)2
= Area Aptitude x 162
= Area Aptitude x 256
= 128 m2
- A. 80 cms
- B. 90 cms
- C. 50 cms
- D. Data inadequate
Remarks:
Explanation:
Let the length of the rectangle be 'x' and breadth of the rectangle be 'y' According to the question: 2(x + y) - x = 100 2x + 2y - x = 100 x + 2y = 100 From this we cannot find 'y' (breadth), so the given data is inadequate.
- A. 5: 4
- B. 2.25 : 1
- C. 4: 5
- D. 4: 7
Remarks:
Explanation:
The ratio between the new area and the original area of the square can be found by using the formula for the area of a square and the percentage increase in the side length. The original area of the square is s^2, where s is the side length. After the side length is increased by 50%, the new side length is 1.5s. The new area of the square is (1.5s)^2 = 2.25s^2. To find the ratio between the new area and the original area, we divide the new area by the original area: 2.25s^2 / s^2 = 2.25. Therefore, the ratio between the new area and the original area of the square can be represented as 2.25 : 1 which means for every 1 unit of original area, the new area is 2.25 unit.
- A. 420 cm<sup>2</sup>
- B. 380 cm<sup>2</sup>
- C. 480 cm<sup>2</sup>
- D. 410 cm<sup>2</sup>
Remarks:
Explanation:
Let length = X and breadth = Y. Then, 2 (X + Y) = 92 OR X + Y = 46 AND X^2 + Y^2 = (34)^2 = 1156. Now, (X + Y)^2 = (46)^2 ⇔ (X2 + Y2) + 2XY = 2116 ⇔ 1156 + 2XY = 2116 ⇒ XY=480 ∴ Area = XY = 480 cm2
- A. 9 cm
- B. 18 cm
- C. 27 cm
- D. 28 cm
Remarks:
Explanation:
Let breadth = X. Then, length = 3X. Then, (3X - 9) (X + 9) = 3X * X + 81 ⇒3X2+27X-9X-81=3X2+81 18X=162 ⇒X=9 cm ∴ Length of the rectangle = 9 cm
- A. 3 : 17
- B. 9 : 49
- C. 24 : 35
- D. 8 : 23
Remarks:
Explanation:
Let the diagonals of the squares be 3X and 7X respectively. Ratio of their areas = (1/2)*(3X)2 :( 1/2)*(7X)2 = 9X2: 49X2 = 9: 49.
- A. 814
- B. 816
- C. 700
- D. 724
Remarks:
Explanation:
Length of largest tile = H.C.F. of 3034 cm and 1804 cm = 82 cm. Area of each tile = (82 x 82) cm^2. Required number of tiles 3034x1804/82x82 = 37x22=814.
- A. 34.56 %
- B. 32.43 %
- C. 29.45 %
- D. 45.24 %
Remarks:
Explanation:
Let each side of the square be X. Then, area = X^2. New side =(116X/100) =(29X/25). New area = (29X/25)^2 Increase in area = (29X/25)^2 - X^2 =841/625X^2 - X^2=216/625X^2 ⇒ Increase% = [(216/625X^2x1/(X^2))*100] % = 34.56%.