- A2%
- B2.02%
- C4%
- D4.04%
Time Taken:
Correct Answer:
Wrong Answer:
Percentage: %
The percentage error in the calculated area of the square is 4.04%.
This is calculated by taking the difference between the actual area and the measured area, and then expressing it as a percentage of the actual area.
In this case, the actual area is 100cm x 100cm = 10000 cm2 and the measured area is 102cm x 102cm = 10404 cm2
The difference (10404 - 10000) = 404 cm2 which is 4.04% of the actual area.
Side of Square = 5 cm, and
length of one side of rectangle = 5/2 = 2.5 cm
Let the length of the other side of the rectangle = B
As per the question:
Area of rectangle = Area of square
Length x Breadth = Side x Side
2.5 * B = 5 * 5
B = 25/2.5
B = 10 cm
Let the breath = x So, the Length = 3x Perimeter of a rectangle = 2 (Length + Breadth) So, 2 (3x + x) = 106 6x + 2x = 106 8x = 106 x = 104/8 = 13 Now, Breadth = 13, so, length = 13 * 3 = 39 So, its area = Length * Breadth = 39 * 13 = 507 sq. m.
Let the length of the rectangle be 'x' and breadth of the rectangle be 'y' According to the question: 2(x + y) - x = 100 2x + 2y - x = 100 x + 2y = 100 From this we cannot find 'y' (breadth), so the given data is inadequate.
Ratio between the sides of rectangle = 3: 4 Let the ratio constant be x then, Length = 3x and breadth = 4x Area = L x B 7500=3x × 4x=12x^2 7500/12= x^2=625 x=25 Length = 3 x 25 = 75 m, and Breadth = 4 x 25 = 100 m Perimeter = 2(75 + 100) = 2 x 175 = 350 m Cost of fencing 1 meter = 25 paise Cost of fencing 350 m = 350 x 25 = 8750 paise In rupees: Rs. 87.50
Length of the hall = 20 m, Breadth of hall = 15 m, Area of hall = L x B = 20 x 15 = 300 m2 Length of hall with verandah = 20 + 2.5 + 2.5 = 25 m, Breadth of hall with verandah = 15 + 2.5 + 2.5 = 20 m, Area of hall with verandah = 25 x 20 = 500 m2 Area of verandah = area of hall with verandah - area of hall = 500 - 300 = 200 m2 Cost of flooring the verandah is Rs. 3.50 per square meter. So, the cost of flooring the entire verandah = 3.50 * 200 = Rs. 700
Side of first square = (80/4) = 20 cm; Side of second square = (64/4)cm = 16 cm. Area of third square = [(20)^2 - (16)^2] cm^2 = (400 - 256) cm^2 = 144 cm^2. Side of third square = √144 cm = 12 cm. Required perimeter = (12 x 4) cm = 48 cm.
Length of largest tile = H.C.F. of 3034 cm and 1804 cm = 82 cm. Area of each tile = (82 x 82) cm^2. Required number of tiles 3034x1804/82x82 = 37x22=814.
Let each side of the square be X. Then, area = X^2. New side =(116X/100) =(29X/25). New area = (29X/25)^2 Increase in area = (29X/25)^2 - X^2 =841/625X^2 - X^2=216/625X^2 ⇒ Increase% = [(216/625X^2x1/(X^2))*100] % = 34.56%.