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QThe perimeters of two squares are 80 cm and 64 cm, respectively. Determine the perimeter of a third square whose area equals the difference between the two squares' areas.
ID: #5334
Area
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Side of first square = (80/4) = 20 cm; Side of second square = (64/4)cm = 16 cm. Area of third square = [(20)^2 - (16)^2] cm^2 = (400 - 256) cm^2 = 144 cm^2. Side of third square = √144 cm = 12 cm. Required perimeter = (12 x 4) cm = 48 cm.
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