#include<stdio.h>
int main() {
int arr1[30], arr2[30], res[60];
int i, j, k, n1, n2;
printf("\nEnter no of elements in 1st array :");
scanf("%d", &n1);
for (i = 0; i < n1; i++) {
scanf("%d", &arr1[i]);
}
printf("\nEnter no of elements in 2nd array :");
scanf("%d", &n2);
for (i = 0; i < n2; i++) {
scanf("%d", &arr2[i]);
}
i = 0;
j = 0;
k = 0;
// Merging starts
while (i < n1 && j < n2) {
if (arr1[i] <= arr2[j]) {
res[k] = arr1[i];
i++;
k++;
} else {
res[k] = arr2[j];
k++;
j++;
}
}
/* Some elements in array 'arr1' are still remaining
where as the array 'arr2' is exhausted */
while (i < n1) {
res[k] = arr1[i];
i++;
k++;
}
/* Some elements in array 'arr2' are still remaining
where as the array 'arr1' is exhausted */
while (j < n2) {
res[k] = arr2[j];
k++;
j++;
}
//Displaying elements of array 'res'
printf("\nMerged array is :");
for (i = 0; i < n1 + n2; i++)
printf("%d ", res[i]);
return (0);
}
Enter no of elements in 1st array : 4
11 22 33 44
Enter no of elements in 2nd array : 3
10 40 80
Merged array is : 10 11 22 33 40 44 80
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.