1
21
321
4321
54321
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=1; i<=N; i++)
{
// Logic to print spaces
for(j=1; j<=N-i; j++)
{
printf(" ");
}
// Logic to print numbers
for(j=i; j>=1; j--)
{
printf("%d", j);
}
printf("\n");
}
return 0;
}
1
21
321
4321
54321
1 21 321 4321 54321
Logic of the above pattern is simple and similar to the previous number pattern that we just printed. In this pattern we only need to add logic of printing extra trailing spaces before the number gets printed. You can hover on to the pattern to see or count total spaces printed per row. The total number of spaces printed per row is N - i (where N is the total number of rows to be printed and i is the current row number).
Step-by-step descriptive logic of the printing spaces:
Finally you are done, lets now implement this on code.
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.