5 45 345 2345 12345
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=N; i>=1; i--)
{
// Logic to print numbers
for(j=i; j<=N; j++)
{
printf("%d", j);
}
printf("\n");
}
return 0;
}
Enter N: 5
5
45
345
2345
12345
5 45 345 2345 12345
In the above pattern there are N rows (where N is the total number of rows to be printed). As you know that to iterate N times, you can either go from 1-N or from N-1. Here in our case we will iterate though rows from N-1, since the pattern printed is in descending order. Each row contains exactly N - i + 1columns (where i is the current row number).
Step-by-step descriptive logic:
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.