56789 4567 345 23 1
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int i, j, k, N;
printf("Enter N: ");
scanf("%d", &N);
for(i=N; i>=1; i--)
{
k = i;
// Logic to print numbers
for(j=1; j<=i; j++, k++)
{
printf("%d", k);
}
printf("\n");
}
return 0;
}
Enter N: 5
56789
4567
345
23
1
56789 4567 345 23 1
The above pattern consists of N rows (where N is the total rows to be printed). Now to iterate N times you can either go from 1-N or from N-1. Here in our case we will go from N-1 as the pattern printed is in decreasing order. Each row contains i columns (where i is the current row number). Note that the first row is row 5, second is 4 and so on last row is 1.
Step-by-step descriptive logic:
First understand the algorithm carefully. Then study the program line-by-line and compare it with the output. Finally, review the explanation section to strengthen your logic and programming understanding.
Rewrite the program without looking at the code. Modify values, conditions or logic and run it again. This helps improve confidence and strengthens coding skills much faster.