[String]

Question:

Find the output:

System.out.println(
"RocKet".substring(0, 4)
.compareTo("Rock".replace('m', 'o'))
);

Question

[String]

Question:


Find the output:



System.out.println(
    "RocKet".substring(0, 4)
    .compareTo("Rock".replace('m', 'o'))
);

Accepted Answer

Answer:


-32


Explanation:


Let us evaluate the expression step-by-step.


Step 1: substring(0, 4)


"RocKet".substring(0, 4)



The substring method takes characters from index 0 to index 3.



R  o  c  K  e  t
0  1  2  3  4  5



Result:



"RocK"


Step 2: replace('m', 'o')


"Rock".replace('m', 'o')



The word "Rock" does not contain the character 'm'.
So no replacement occurs.



Result:



"Rock"


Step 3: compareTo()


"RocK".compareTo("Rock")



compareTo() compares strings character by character using ASCII values.



Comparison:



R = R
o = o
c = c
K ≠ k



ASCII values:



K = 75
k = 107



Difference:



75 - 107 = -32



Therefore:



Output = -32


Conclusion:


    substring(0,4) → "RocK"
    replace('m','o') → "Rock"
    compareTo() compares ASCII values
    Final Output = -32

[String] Question: Find the output: System.out.println( "RocKet".substring(0, 4) .compareTo("Rock".replace('m', 'o')) );

Answer with Explanation

[String]

Question:

Find the output:

System.out.println( "RocKet".substring(0, 4) .compareTo("Rock".replace('m', 'o')) );