General Aptitude › Problems on Ages › Question #4393
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QThe average of the ages of a man and his daughter is 34 years. If the respective ratio of their ages four years from now is 14: 5, what is daughter's present age?

ID: #4393 Problems on Ages 507 views
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  • A 10 years ✔ ✖
  • B 12 years ✔ ✖
  • C 18 years ✔ ✖
  • D none of these ✔ ✖
Correct Answer

Explanation

Let the present ages of the man and his daughter be x and y years respectively.
The average of their ages is (x + y)/2 = 34 years.
Four years from now, the ages of the man and his daughter will be (x + 4) and (y + 4) years respectively.
The ratio of their ages four years from now is (x + 4) : (y + 4) = 14:5.
Solving these equations for x and y, we get x = 52 and y = 16
Therefore, the daughter's present age is 16 years.

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