Arithmetic Aptitudes › Problems on Ages › Question #4394
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QTen years ago, the father's age was three times the age of his son. In ten years, the father's age will be twice the age of his son. What is the ratio of their current ages?

ID: #4394 Problems on Ages 372 views
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#4394Q ID
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  • A 8:5 ✔ ✖
  • B 7:3 ✔ ✖
  • C 9:5 ✔ ✖
  • D 5:2 ✔ ✖
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Explanation

Let the present age of the son be x + 10 years.
The age of the father 10 years ago was thrice the age of his son, which means that the father's age 10 years ago was 3 * x years.
Ten years from now, the father's age will be twice that of his son, which means that the father's age will be 2 * (x + 20) years.
Since the father's age 10 years ago was thrice the age of his son, and the father's age 10 years from now will be twice that of his son, this means that  (3x +20) = 2 * (x + 20).
Solving this equation for x, we get x = 20.
Therefore, the present ages of the father and son are (20 * 3)+10 = 70 years and 30 years respectively, and the ratio of their ages is 70:30 = 7:3.

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