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QWhat is the average of the squares of the first 6 consecutive even numbers starting from 2 to 12, where the last even number is 12?
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The average of the squares of the first 6 consecutive even numbers starting from 2 to 12,
where the last even number is 12, is 60.66. To find this, we can use the following steps:
The first 6 consecutive even numbers starting from 2 to 12, where the last even number is 12, are 2, 4, 6, 8, 10, and 12.
The average of the squares of these numbers is (2 * 2 + 4 * 4 + 6 * 6 + 8 * 8 + 10 * 10 + 12 * 12) / 6 =
(4 + 16 + 36 + 64 + 100 + 144) / 6
= 13 * 14 / 3
= 182 / 3
= 60.66
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